Motion with Constant Acceleration

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Motion with Constant Acceleration: Overview

This topic covers concepts, such as, Uniformly Accelerated Motion, Sign Convention in Accelerated Motion, Reaction Time Calculation under Constant Acceleration & Observer and Escalator Problems etc.

Important Questions on Motion with Constant Acceleration

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The figure shows the v-t graph of a particle moving in a straight line. Starting from rest, the time after which the particle returns to its starting position is

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The velocity-time graph of the particle moving along a straight line is shown. The rate of acceleration and deceleration is constant and it is equal to 5 m s-2. If average velocity during the motion is 20 m s-1, then find the value of t
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An object moving with uniform acceleration has a velocity of 12.0 cm s-1 in the positive x direction when its x coordinate is 3.00 cm. If its x coordinates 2.00 s later is -5 cm, what is its acceleration?

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At a distance L=400 m from the traffic light brakes are applied to a locomotive moving at a velocity v=54 km hr-1. Determine the position of the locomotive relative to the traffic light 1 minute after the application of the brakes if its acceleration is - 0.3 m s-2.

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A body starts from rest, what is the ratio of the distances traveled by the body during the 4th and 3rd seconds?

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A body dropped from top of a tower falls 40 m during the last two seconds of its fall. The height of tower is   (g = 10 m s 2 )

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A boy standing at the top of a tower of 20 m height drops a stone. Assuming  g=10m s2, the velocity with which it hits the ground is

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A particle moves a distance x in time t according to equation   x= (t+5) 1 .  The acceleration of particle is proportional to:

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A particle has initial velocity (3 i ^ +4 j ^ ) and has acceleration (0.4 i ^ +0.3 j ^ ). Its speed after 10 s is:

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A ball is dropped from a high rise platform at, t=0 starting from rest. After 6 s another ball is thrown downwards from the same platform with the speed v. The two balls meet at, t=18 s. What is the value of v(Take, g=10 m s-2 )

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What will be the ratio of the distances moved by a freely falling body from rest in fourth and fifth seconds of the journey?

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The position x of a particle with respect to time t along x-axis is given by, x=9t2t3 where, x is in meters and t is in seconds. What will be the position of this particle when it achieves maximum speed along the +ve x direction?

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Two bodies, A (of mass 1 kg) and B (of mass 3 kg), are dropped from heights of 16 m and 25 m, respectively. The ratio of the times taken by them to reach the ground is

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A ball is thrown vertically upwards. It has a speed of 10 m s-1 when it has reached one half of its maximum height. How high does the ball rise?

(Take, g=10 m s-2)

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The displacement x of a particle varies with time t as  x = aeαt+beβt  , where a, b,  αandβ  are positive constants. The velocity of the particle will

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A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw, so that more than two balls are in the air at any time?   [Giveng=9.8 m s 2 ]

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If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is

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A stone is thrown vertically upwards with kinetic energy K. The kinetic energy at the highest point is

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The displacement of a particle is represented by the following equation : s=3 t 3 +7 t 2 +5t+8 where s is in metres and t is seconds. The acceleration of the particle at t=1 s is

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A car moving with a speed of 40 km h-1 can be stopped by applying brakes at least after 2 m. If the same car is moving with a speed of 80 km h-1, what is the minimum stopping distance?